Question: There are 12 men on an island. 11 weigh the same. 1 man is heavier or lighter. There is one seasaw you can use only 3 times. How do you find the odd man out? Is this riddle possible?
Answer: First gauge 6 versus 6(1st use)
The 6 which are heavier ought to be partitioned into gatherings of 3 and weighed(2nd use)
The 3 who are heavier ought to be seperated and gauge any 2 of them (third use) If one of the 2 is heavier then you get the answer.If they gauge the equivalent, at that point the third individual who wasn’t weighed is the heavier individual.