A man has nine children, born at regular intervals. The sum of their squares of their ages is equal to the square of his own age.

Math Riddle:  A man has nine children, born at regular intervals. The sum of their squares of their ages is equal to the square of his own age.

What are the ages of the children?

Answer: The correct answer is 2  –  5  –  8  –  11  –  14  –  17  –  20  –  23  –  26

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